![]() ![]() ![]() And then once again, we have to make sure that our units work out. So t plus 42 minutes is how long that the gryphon has been So if t is how many minutes that the dragon has beenįlying east of the castle, well, then the gryphon is The castle 42 minutes before the dragon passed it. Have flown by that point? Well, the gryphon passed So they tell us that the gryphon is flying at 50 kilometers per hour, so 50 kilometers per hour. Maybe I'll simplify it a little bit later. Now we could try to simplify this, but I'll leave it like this for now. The dragon would have flown after t minutes is going toīe 225t over 60 kilometers. This hour cancels with that hour in the numerator and the denominator, and this minutes cancels This is in minutes, while the rate is given ![]() So the distance is going to be the rate, 225 kilometers per hour, times the time, so times t minutes. Well, the dragon's flyingĪt 225 kilometers per hour. So let's think about the distance that the dragon would haveįlown in that t minutes. That the dragon has flown, dragon flown since castle, since castle and catches up, catches up. Variable to be equal to t, the number of minutes It catches up to the gryphon? So let's set that All right, so the question is, how many minutes will If you can figure this out before we do this together. Kilometers east of the castle will they be at that time? So pause this video and see ![]() It catches up to the gryphon? They also ask us how many The dragon have flown since passing the castle when The dragon continue flying east at the same speeds. Then, 42 minutes later, a dragon also flew east over the castle. That a gryphon flew east over a castle at 50 kilometers per hour. ![]()
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